五子棋机器人代码优化：如何简化重复代码？

五子棋机器人,简化代码

问题：

我花了几天的时间用vue写了一个五子棋，与机器人对战

但是我感觉里面代码很多重复的部分，想要简化写法，希望大家帮我看看

重复代码：

function airPoint() {

  //机器人四个连在了一起，那应该要放四个旁边
  console.log(fourDetial, 'fourDetial')
  if (fourDetial && JSON.stringify(fourDetial) !== '{}') {

    if (fourDetial.type === 1) {
      if (fourDetial.geyi) {
        for (let i = fourDetial.x; i > fourDetial.x - fourDetial.times + 1; i--) {
          if (boxs.value[i][fourDetial.y].place === 0) {
            boxs.value[i][fourDetial.y].place = 2
            fourDetial = determineEquare3(4, 2, { x: i, y: fourDetial.y, place: 2 })
            airPlace.push((i) * row.value + fourDetial.y)
            curUser.value = 1
            return
          }
        }
      }
      else
        if (boxs.value[fourDetial.x + 1]?.[fourDetial.y]?.place === 0) {
          boxs.value[fourDetial.x + 1][fourDetial.y].place = 2
          fourDetial = determineEquare3(4, 2, { x: fourDetial.x + 1, y: fourDetial.y, place: 2 })
          airPlace.push((fourDetial.x + 1) * row.value + fourDetial.y)
          curUser.value = 1
          return
        } else if (boxs.value[fourDetial.x - fourDetial.times]?.[fourDetial.y]?.place === 0) {
          boxs.value[fourDetial.x - fourDetial.times][fourDetial.y].place = 2
          fourDetial = determineEquare3(4, 2, { x: fourDetial.x - fourDetial.times, y: fourDetial.y, place: 2 })
          airPlace.push((fourDetial.x - fourDetial.times) * row.value + fourDetial.y)

          curUser.value = 1
          return
        }
    } else if (fourDetial.type === 2) {
      if (fourDetial.geyi) {
        for (let j = fourDetial.y; j > fourDetial.y - fourDetial.times + 1; j--) {
          if (boxs.value[fourDetial.x][j].place === 0) {
            boxs.value[fourDetial.x][j].place = 2
            fourDetial = determineEquare3(4, 2, { x: fourDetial.x, y: j, place: 2 })
            airPlace.push((fourDetial.x) * row.value + j)
            curUser.value = 1
            return
          }
        }
      }
      else if (boxs.value[fourDetial.x]?.[fourDetial.y + 1]?.place === 0) {
        boxs.value[fourDetial.x][fourDetial.y + 1].place = 2
        fourDetial = determineEquare3(4, 2, { x: fourDetial.x, y: fourDetial.y + 1, place: 2 })
        airPlace.push((fourDetial.x) * row.value + fourDetial.y + 1)

        curUser.value = 1
        return
      } else if (boxs.value[fourDetial.x]?.[fourDetial.y - fourDetial.times]?.place === 0) {
        boxs.value[fourDetial.x][fourDetial.y - fourDetial.times].place = 2
        fourDetial = determineEquare3(4, 2, { x: fourDetial.x, y: fourDetial.y - fourDetial.times, place: 2 })
        airPlace.push((fourDetial.x) * row.value + fourDetial.y - fourDetial.times)

        curUser.value = 1
        return
      }
    } else if (fourDetial.type === 3) {
      if (fourDetial.geyi) {
        let i
        for (let j = fourDetial.y - 1; j > fourDetial.y - fourDetial.times + 1; j--) {
          i = fourDetial.x - (fourDetial.y - j)
          if (boxs.value[i]?.[j]?.place === 0) {
            boxs.value[i][j].place = 2
            fourDetial = determineEquare3(4, 2, { x: i, y: j, place: 2 })
            airPlace.push((i) * row.value + j)
            curUser.value = 1
            return
          }
        }
      }
      else
        if (boxs.value[fourDetial.x + 1]?.[fourDetial.y + 1]?.place === 0) {
          boxs.value[fourDetial.x + 1][fourDetial.y + 1].place = 2
          fourDetial = determineEquare3(4, 2, { x: fourDetial.x + 1, y: fourDetial.y + 1, place: 2 })
          airPlace.push((fourDetial.x + 1) * row.value + fourDetial.y + 1)

          curUser.value = 1
          return
        } else if (boxs.value[fourDetial.x - fourDetial.times]?.[fourDetial.y - fourDetial.times]?.place === 0) {
          boxs.value[fourDetial.x - fourDetial.times][fourDetial.y - fourDetial.times].place = 2
          fourDetial = determineEquare3(4, 2, { x: fourDetial.x - fourDetial.times, y: fourDetial.y - fourDetial.times, place: 2 })
          airPlace.push((fourDetial.x - fourDetial.times) * row.value + fourDetial.y - fourDetial.times)

          curUser.value = 1
          return
        }
    } else if (fourDetial.type === 4) {
      if (fourDetial.geyi) {
        let i
        for (let j = fourDetial.y; j < fourDetial.y + fourDetial.times - 1; j++) {
          i = fourDetial.x - (j - fourDetial.y)
          if (boxs.value[i]?.[j]?.place === 0) {
            boxs.value[i][j].place = 2
            fourDetial = determineEquare3(4, 2, { x: i, y: j, place: 2 })
            airPlace.push((i) * row.value + j)
            curUser.value = 1
            return
          }
        }
      }
      else if (boxs.value[fourDetial.x + 1]?.[fourDetial.y - 1]?.place === 0) {
        boxs.value[fourDetial.x + 1][fourDetial.y - 1].place = 2
        fourDetial = determineEquare3(4, 2, { x: fourDetial.x + 1, y: fourDetial.y - 1, place: 2 })
        airPlace.push((fourDetial.x + 1) * row.value + fourDetial.y - 1)
        curUser.value = 1
        return
      } else if (boxs.value[fourDetial.x - fourDetial.times]?.[fourDetial.y + fourDetial.times]?.place === 0) {
        boxs.value[fourDetial.x - fourDetial.times][fourDetial.y + fourDetial.times].place = 2

以上就是五子棋机器人代码优化：如何简化重复代码？的详细内容，更多请关注其它相关文章！